What is the procedure for using mean and median to determine whether the data is skewed, and if so, in what direction?

  1. a. Imply: (14+13+15+21+19+24+25+28+25+31)/10 = 22.3 Median: The median is the center worth when the info is organized so as. As the info has 10 values, the median can be the worth on the fifth place, which is 25%.

b. To find out whether or not the info is skewed, one can evaluate the imply and median. If the imply is bigger than the median, it means that the info is positively skewed. If the imply is lower than the median, it means that the info is negatively skewed.

c. On this case, the imply is 22.3 and the median is 25%. Because the imply is lower than the median, it means that the info is negatively skewed.

  1. a. The random variable shall be steady. A steady random variable can tackle any worth inside a given interval, and thus is just not restricted to sure values.

b. The info shall be quantitative. A quantitative random variable will be measured and may have a numerical worth.

  1. We are able to use the usual regular distribution desk and the z-score method to search out the likelihood of the driving force getting the pit cease in a brief sufficient time to take care of his lead.

Z-score = (12.5 – 13.2)/0.9 = -0.78

Utilizing the usual regular distribution desk, we will discover that the likelihood of a z-score being lower than -0.78 is 0.22. Subsequently, the likelihood of the driving force getting the pit cease in a brief sufficient time to take care of his lead.

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